Question

A projectile is thrown into space so as to have a maximum possible horizontal range of 400 metres. Taking the point of projection as the origin the CO-ordinate of the point where the velocity of the projectile is minimum are

Answer 1

maximum height attained by the projectile is at the half of its range so the answer is 200m and it's min velocity is at highest point

Answer 2

The velocity will be minimum at the highest point.

So,x-co-ordinate is 4002 m ,i.e.,200m

Again,y=hmax=v2sin245∘2g

⇒v24g

⇒14×400m=100m