A projectile is thrown into space so as tohave a max. possible horizontal range of 400mts. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum are? can you show how to solve it?
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I am not solving it here. I am giving just a hint how to solve it.
•Note: Velocity of a projectile is minimum at the the highest point of it's flight and at middle point as far as horizontal displacement is concerned. Also note that angle of projection should be 45°.
•Therefore the required coordinate will be (Range/2, Maximum height).
•Initial velocity can be calculated by using range formula.
•By using initial velocity maximum height can be calculated.
•Using range and height you can find the coordinate as required in the question.
Hope this helps. For clarification or discussion please comment. You may follow me for more from me. Thanks!
•Note: Velocity of a projectile is minimum at the the highest point of it's flight and at middle point as far as horizontal displacement is concerned. Also note that angle of projection should be 45°.
•Therefore the required coordinate will be (Range/2, Maximum height).
•Initial velocity can be calculated by using range formula.
•By using initial velocity maximum height can be calculated.
•Using range and height you can find the coordinate as required in the question.
Hope this helps. For clarification or discussion please comment. You may follow me for more from me. Thanks!
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