a projectile is thrown making an angle of 60° with the horizontal with velocity of 10 m/s. The maximum height attained by the projectile is [Take g = 10 m/s2]
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angle = 60 Vi = 10 m/s g = 10 m/s H
H = vi2 sin2θ / 2 g = (10)2 (sin 60)2 / 2 * 10 = 100 * 0.866 *0.866 /20 = 3.74 m
Explanation:
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