Question

A projectile is thrown upwards with the velocity of 49m/s and makes an angle of 30° with horizontal, find it's velocity after 2 seconds.

Answer 1

Given that,

• Velocity = 49 m/s

• Angle with horizontal = 30°

• Velocity after 2 seconds = ?

As we know,

⇒ U(y) = 49*sin30°  = 49/2

⇒ U (x) = 49 *cos 30°

⇒ 49√3/2

For total time of flight…

• S(y) = 0

• A(y) = -10

• U(y) = 49/2

• t = ?

⇒ 0=49/2*t - 1/2*10*t^2

⇒ 49/2 * t= 5t^2

⇒ t = 49/10s

Now for range

S(x)=?

U(x)= 49*√3/2

t = 49/10s

Range = S(x)=u(x)*t

⇒  49*√3/2*49/10

⇒  207.93

⇒ ~208m approx.