A projectile is thrown with an initial velocity of
(
a
^
i
+
b
^
j
)
m/s
.
If the range of projectile is twice, the maximum height reached by it, then
Answers
Answered by
0
for range,
a=0
so, s=bt
fo hight,
a=-g,
T=t/2
so, s=ut/4-1/2gt²
according to question,
range =2h,satisfying this ,we will get...
2a-4b=gt
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