Question

a projectile of mass 5m is projected at 40m/s at an angle of 75 degree to the horizontal.it explodes at its highest point into 2 fragments. if one part falls at the point of projection, where does the other part fall? A. 60M B. 40M C. 100M D. 80M

Answer 1

The range of the second part of projectile is 80 m.

Option (D) is correct.

Explanation:

We are given that:

• Mass of projectile = 5 m
• Speed of projectile "u" = 40 m/s
• The angle of projection "Θ" = 75 degree
• To Find: The point where other part falls = ?

Solution:

R = m x o + 4m (R + x ) / 5 m

R = 4m ( R + x ) / 5 m

R + x = 5 R / 4

R = u^2 sin 2 Θ / g

R = (40)^2 x sin 150 / 10

R = 1600 x 0.5 / 10

R = 1600 x 0.05 = 80 m

Thus the range of the second part of projectile is 80 m.