Question

A projectile of mass m ,change z ,initial speed u and impact parameter b is scattered by a heavy nucleus of charge Z as shown in figure .Use angular momentum and energy conservation to obtain a formula connecting the minimum distance of the projectile from the nucleus to these parameters .Show that for b=0
,the distance s reduces to the distance of the closest approach r0 ,given by the formula.
$\tt \: r _{0} = \dfrac{1}{4 \pi \varepsilon} _{0}. \dfrac{z \: z ^{ .} {e}^{2} }{ \frac{1}{2} m {u}^{2} }$
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Answer 1

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