Question

a projectile shot out at an angle of 35 degree strikes the ground at horizontal distance of 4 kilometre from the point of projection calculate the initial velocity time of flight maximum altitude velocity at the point of maximum altitude

Answer 1

Answer:

the initial velocity = 206 m/s

Time of Flight = 23.6 s

maximum altitude velocity = 168.7 m/s

Explanation:

Let say Velocity = V

angle of 35 degree

Vertical Velocity = VSin35

Horizontal Velocity = Vcos35

Time of Flight = 2 * ( VSin35/g)

Horizontal Distance = Vcos35 * 2 * ( VSin35/g)

=>V²Sin70/g  = 4000 ( 4km = 4000 m)

=> V = 206 m/s

the initial velocity = 206 m/s

Time of Flight = 2 * ( VSin35/g) = 23.6 sec

maximum altitude velocity = horizontal Velocity = Vcos35 = 168.7 m/s