Question

Three identical impedances are connected in delta to a 3-phase supply of 400 V.The line current is 34.65 A and the total power taken from the supply is 14.4 KW .Calculate the resistance (in SI unit)

Answer 1

Answer:

Answer:

12Ω

Step-by-step explanation:

Given,

$V_{L}=400V\\ I_{L} =34.65A\\P=14.4KW$

To,Find

$R_{Ph} =?(resistance)$

See the attachment for the solution because it includes some mathematical formula,In the attachment $Z_{Ph}$ is  impidence and cosФ is power factor.