A projectile will cover the maximum vertical distance in the minimum time when the angle of its projection with the vertical is:
(a) 0 ⁰
(b) 30⁰
(c) 60 ⁰
(d) 90⁰
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Answer:
I think (d) but iam not sure
Explanation:
Maximum height of projection is
H=(V^2sin^A)÷2g where A is the angle of projection
Therefore H is maximum when sinA=1
therefore A=90
Iam not sure about the answer
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