A proton accelerated from rest through potential difference V Volts has a wavelenght I associated with it . An alpha particle in order to have same wavelength must be accelerated from rest through how much potential difference?
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Solution
λ=h2meV−−−−−√-------(i)
λ=h2(4m)(2e)V′−−−−−−−−−−√-------(ii)
Equating equation (i) & (ii) we have
2meV=2(4m)(2e)V′
So V′=V8.
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