Question

A proton and alpha particle having the same kinetic energy are in turn passed through a region of uniform magnetic field acting normal to the planes of the paper and travel in circular paths deduce the ration of the radii of the circular path described by them ..??​

Answer 1

Explanation:

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Answer 2

A Proton

Has A Mass= M And Charge Q

Alpha Particle

Has A Mass M' = 4m And Charge Q' = 2q

K.E Of Proton = K.E Of Alpha Particle

1/2mv^2 = 1/2m'v'^2

${v}^{2} = 4 {vdash}^{2}$

$\frac{v}{vdash} = 2$

Radius Of Charged Particle In Uniform Magnetic Field Is R =Mv/Qb using this we get,

$\frac{rdash}{r} = \frac{mdash \times vdash \times q}{m \times v \times qdash}$

$\frac{rdash}{r} = \frac{4m \times q \times 1}{m \times 2q \times 2}$

$\frac{rdash}{r} = \frac{1}{1}$

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