Question

integrate by substitution​

Answer 1

Answer:

$put \: \: \frac{1}{ {x}^{2} } = t \\ \\ - \frac{ 2}{ {x}^{3} } dx = dt \\ \\ \frac{dx}{ {x}^{3} } = - \frac{dt}{2} \\ \\ = - \frac{1}{2} intigration \: {e}^{t} = - \frac{ {e}^{t} }{2} + c \\ \\ = - \frac{ {e}^{ \frac{1}{ {x}^{2} } } }{2} + c$