a proton and an alpha particle, accelerated through same potential difference, enter in a region of uniform magnetic field with their velocities perpendicular to the field. compare the radii of circular paths followed by them.
Answers
Answered by
20
Answer:
Explanation:
Radius of circular path r of a charge q with mass m and moving with velocity v in a magnetic field B is given by
If the charge q is accelerated through potential difference V then
Therefore
Therefore, for the proton
And, for the alpha particle
Thus,
We know that
and
Thus
Hope this helps.
Answered by
0
Answer:
r_p : r_alpha = 1 : √2
Explanation:
work done due to potential difference = kinetic energy of the both charge particle
Now from mv^2/r = qvB, we get r = mv/qB
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