Question

A proton and an alpha particle have same de broglie wavelength determine the ratio of acceleration

Answer 1

According, the shortest wavelength shall be of the alpha particle. The wave length of the proton will be about 4 times that of the alpha particle ( mass of an alpha particle= about 4 times mass of a proton).The wave length of electron is largest. De broglie wavelength lambda=h/mv, where m is the mass of the particle.

Answer 2

$\huge \sf Alpha \: particles$

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★Since, de Broglie wavelength is given by

$\huge\tt \red{\lambda=\frac{h} {p} }$

Here, p is momentum of particle

Also know that

★Kinetic Energy :

$\huge\tt \orange{K=\frac{p^2} {2m}}$

If we solve,

$\large\tt{\lambda=\frac{h} {\sqrt{2mK} } }$

Here, we can clearly see that de Broglie wavelength is inversely proportional to square root of their masses.

Therefore, the mass of proton $\large\tt{^1_1H}$

H is 1836 times more than an electron and mass of alpha particle $\large\tt{^4_2H}$

H four times that of proton.

Therefore alpha particles have higher wavelength.