Question

a proton and an electron are placed 1.6 cm apart in free space.find the magnitude of electrostatic force between them.what is the nature of force?​

Answer 1

Therefore,the nature of force is attractive

Answer 2

Answer:

so answer is 9x10^-25 N/attraction  

Explanation:

Electrostatic forces are non-touch forces; they pull or push on gadgets with out touching them. Rubbing a few substances collectively can bring about some thing called 'rate' being moved from one floor to the different. Charged gadgets pull on different uncharged gadgets and can both push or pull on different charged gadgets.

so given rate of a proton =1.6x10^-19 c

rate of electron is =1.6x10^-19 c

.distance r = 1.6x10^-2 meter

we should locate the importance of electrostatic pressure among them

F=kq1q2/r²

 =nine x 10 ^nine x(1.6x10^-19)²  /(1.6x10^-2)²

so

F= 9x10^-25 N/attraction  because of contrary charges

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