Question

a Proton and and an Alpha particle are accelerated through the same potential which one of the two has greater value of de Broglie wavelength less momentum​

Answer 1

Answer:

here

Explanation:

if proton and alpha particles is accelerated through same potential then

proton will have greater value of de-broglie wavelength because

$lambda \: proton \: = 0.286 \div \sqrt{ potential \: difference}$

while

$lambda \: alpha \: = = 0.101 \div \sqrt{potential \: difference}$