Question

A proton and deuteron have the same de broglie wavelength explain which has more kinetic energy

Answer 1

De broglie wavelength equation is,             λ = h/mv = h/√2mE  (where E is kinetic energy)  Given wavelength are same. So,            $\sqrt{x} 2mx_{123} pEx_{123} p = \sqrt{x} 2mx_{123} dEx_{123} d$