A proton in a cyclotron changes its velocity from 30 km/s north to 40km/s east in 20s. What is the magnitude of average acceleration during this time ???
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Bonjour!
The magnitude of average acceleration during this time will be 2.5 km/s².
See the attached picture for calculations.
Hope this helps...:)
The magnitude of average acceleration during this time will be 2.5 km/s².
See the attached picture for calculations.
Hope this helps...:)
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Answered by
31
Answer: The average acceleration is
Explanation:
Given that,
Velocity from north
Velocity to east
Time t = 20 s
The resultant velocity is
Now, the average acceleration is
Acceleration = resultant velocity/ time
Hence, the average acceleration is .
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