Question

A proton is about 1840 times heavier than an electron. when it is accelerated by a potential difference of 1 kv, its kinetic energy will be

Answer 1

it's kinetic energy is equal to 1.6×(10)^-16 Joule

Answer 2

Answer:

$1.602\times 10^{-16}\ J$

Explanation:

Given:

• u = initial velocity of the proton
• q = charge on a proton = $1.602\times 10^{-19}\ C$

Assume:

• W = work done by the electric force
• K = kinetic energy gain

When the proton is placed accelerated through a potential difference from rest, then the electric force does work on this. This work done by electric force causes a gain in kinetic energy of the proton.

Since the proton is initially assumed to be rest, the initial kinetic energy of the proton is zero. Now, the gain in kinetic energy is equal to the work done by electric force on the proton which is given by:

$W=qV\\\Rightarrow K = 1.602\times 10^{-19}\ C\times 10^3\ V\\\Rightarrow K = 1.602\times 10^{-16}\ J$