Question

A proton is accelerated in a cyclotron in which the magnetic induction is 0.6wb/m^2 what is the frequency of cyclotron

Answer 1

frequency= q*b/2πm

Given:
charge of proton: 1.602*10^-19
mass of proton:1.672*10^-27
magnetic induction:0.6Wb/m^2

Solution:
Substitute values in equation,

=1.602*10^-19*1.672*10^-27/2*3.141*0.6

=2.523*10^-46Hz

Ans : Frequency of cyclotron will be 2.532*10^-46Hz