Question

A Proton is accelerated through a potential difference subjected to a uniform magnetic field acting normal to the velocity of the proton if the potential difference is doubled how will the radius of the circular path described by the proton in the magnetic field change​

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Answer 1

may be proton is accelerated more fastly when it's potential difference is doubled

Answer 2

R= MV/QB

mv= √2mqV, where V is potential difference

R∝ √V

Radius will become √2 times.