Question

A proton is accelerated through a potential difference of 400V to have same de broglie wavelength what potential difference must be applied across doubly ionised 8O16 atom

A.50V. B.12.5V
C.100V. D.none of these​

Answer 1

The potential difference must be V1 = 8.34 × 10^−31 volts.

Correct option is (D).

Explanation:

De-Broglie wavelength (λ) is given by

λ = h / mv

λ = h/ √2mqV

For proton

λ = h√ 2 × 1.67 × 10^−31 × 1.6 × 10^−19 × 400

For oxygen atom

λ1 = h / √2 × 8 × 1.6 × 10^−19 × 16 × V1

For same wavelength, λ = λ1

V1 = 2 × 1.67 × 10^−31 × 1.6 × 10^−19 × 400 / 2 × 8 × 1.6 × 10^−19 × 16

V1 = 8.34 × 10^−31 volts

Thus the potential difference must be V1 = 8.34 × 10^−31 volts.

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If a potential difference of 10.V causes a current of 2.A to flow for 1 minute,how much energy is transferred?

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