A proton is moves between two points whose potential difference is 20v the energy acquire by the proton is
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We know that potential energy U = Vq
V-potential diff
q-charge
Given
V=20v
Proton means charge = 1.602 x 10^-19 c
Now,
U = 20 x 1.602 x 10^-19 = 32.04 x 10^-19 J
Therefore energy acquired by that proton is 32.04 x 10^-19 J
V-potential diff
q-charge
Given
V=20v
Proton means charge = 1.602 x 10^-19 c
Now,
U = 20 x 1.602 x 10^-19 = 32.04 x 10^-19 J
Therefore energy acquired by that proton is 32.04 x 10^-19 J
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