Question

A proton is moving towards North with a velocity of
1.5 x 107ms- in a uniform magnetic field of 5 Tesla directed
eastward. The magnetic force experienced is
(1) 12 x 10-12 N
(2) 12x10-10N
(3) 7.5 x 107N
(4) 5.7x105N​

Answer 1

Answer:

2.4×10-12

Explanation:

charge of proton 1.602×10-19

velocity v =2×107m/s

angle( pie)= 300

magnetic field B=1.5wb/m²

Answer 2

The magnetic force experienced by the proton will be 12 × $10^{-12}$N.

Given:

The velocity of the proton (v) = 1.5 × $10^{7}$ m/s toward the north

The magnetic field (B) = 5 T towards the east

To Find:

The magnetic force experienced by the proton

Solution:

We know,

Magnetic force, F= qvBsin∅ [Here ∅=90° so sin∅ = 1]

F= 1.6 × $10^{-19}$ × 1.5 × $10^{7}$ × 5 = 12 × $10^{-12}$ N.

Hence, the magnetic force experienced by the proton will be 12 × $10^{-12}$N.

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