Question

pls help me for this question​

Answer 1

Step-by-step explanation:

$Given \: Surface \: area \: of \: a \: cubical \: box= \: 24 {(2x - 1)}^{2} {cm}^{2} \\ \: because \: Surface \: area \: of \: a \: cubical \: box= \: 6 {a}^{2} \\ so \: 6 {a}^{2} = 24 {(2x - 1)}^{2} {cm}^{2} \\ = {a}^{2} = \frac{24}{6} {(2x - 1)}^{2} {cm}^{2} \\ = {a}^{2} = 4 {(2x - 1)}^{2} {cm}^{2} \\ = a = \sqrt{4 {(2x - 1)}^{2} {cm}^{2}} \\ then \: \\ side \: of \: cubical \: box \: (a) = \: 2(2x - 1) \: cm \\ then \: \: \: volume \: of \: cubical \: box \: = {side}^{3} \\ = {(2(2x - 1) \: cm)}^{3} \\ = 8 \times ({(2x)}^{3} - {(1)}^{3} - 3 \times {(2x)}^{2} \times 1 + 3 \times 2x \times {1}^{2} ) {cm}^{3} \\ = 8( {8x}^{3} - {12x}^{2} + 6x - 1) {cm}^{3} \\ \\ \\ or \\ \\ volume \: of \: cubical \: box \: = \: ({64x}^{3} - {96x}^{2} + 48x - 8) {cm}^{3}$

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