Question

A proton is released from rest at a distance of 10** from the nucleus of a mercury atom (2=80). The kinetic energy of the proton when it is far away from the nucleus is​

Answer 1

Explanation:

Given here,

q

1

=120×e

q

2

=e ( charge on proton)

It is based on conservation of energy of proton.

2

1

mv

2

=k

R

q

1

q

2

v=

mR

2Kq

1

q

2

Also, we know, de’broglie wavelength,

λ=

mv

h

λ=

2mKq

1

q

2

h

R

Thus,

λ=

2×

3

5

×10

−27

×9×10

9

×120×e

2

h

10×10

−15

λ=

6×10

−8

e

h

×10

−7

λ=

6×10

−8

4.2×10

−15

×10

−7

λ=7×10

−15

m=7 fm