Question

A proton ( mass 1.67 *10^-27 kg ) on striking a neutron

Answer 1

Dear Student,

# Complete question -

Q. A proton (mass 1.67 × 10^-27 kg) on striking neutron ( mass nearly equal to proton) forms a deutron. What would be the velocity of the deutron if it is formed by a proton moving left with a velocity of 7 × 10^6 m/s and a neutron moving right with a velocity of 4 × 10^6 m/s ?

◆ Answer -

v = 1.5×10^6 m/s

◆ Explanation -

# Given -

mp = 1.67×10^-27 kg

mn = 1.67×10^-27 kg

up = 7×10^6 m/s

un = -4×10^6 m/s

# Solution -

Let M be mass of deuteron and v be its velocity.

By law of conservation of momentum,

pi = pf

mp.up + mn.un = M.v

mp.up + mn.un = (mp+mn).v

(1.67×10^-27 × 7×10^6) + (1.67×10^-27 × -4×10^6) = (1.67×10^-27 + 1.67×10^-27) × v

v = (7×10^6 - 4×10^6) / 2

v = 1.5×10^6 m/s

Therefore, velocity of deuteron must be 1.5×10^6 m/s.

Thanks dear...

Answer 2

Explanation:

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