Question

A proton moves at a speed of 7.9 x 103 m/s as it passes through and it is perpendicular to a 0.60 t of uniform magnetic field. the radius of the circular path:

Answer 1

HEYA HERE'S UR ANSWER....

Please refer the attachment.

Hope this helps you quickly........

Answer 2

SOLUTION-'

• F = q v B ( loreng force ) = mv2/r ( centripetal force )
• so
• r= mv2/ qV B apply this formula u will get answers
• reason = as charged particles move perpendicular to magnitic field it move on circle .