Question

a proton moving at velocity v=(-200 m/s)j^ toward and perpendicular to a long straight wire with current i = 350 mA. At the instant
shown, the proton's distance from the wire is d = 2.89 cm. In unit-vector notation, what is the magnetic force on the proton due to
the current?
IT!
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Answer 1

Answer:

v^2=u^2+2as it is the third equation of motion

Explanation:

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