Physics, asked by mjkin7528, 1 year ago

A proton of mass mp collides with a heavy particle at rest


Ramji80906461: Hi

Answers

Answered by stevesmith3
2
A particle makes a head-on-collision with an unknown particle at rest.The proton rebounds back with 4/9 of its initial kinetic energy.Find the ratio of mass of unknown particle to mass of proton assuming the collision to be elastic.



Let m1 and m2 be the masses of the first (moving) and the second (being in rest) particle,Let also u be the velocity of the first particle, and v1 and v2 be the velocities of particles
after collision.

Since the collision is assumed to be elastic we have the momentum of the system is not changed, so

(A) m1*u = m1*v1 + m2*v2Moreover, we also have that the total kinetic energy of both particles is also unchanged, so

m1 * u2 / 2 = m1 * v12 / 2 + m2 * v22 /2By assumption the kinetic energy of the first particle after collision is equal to 4/9 of its initial kinetic energy,
whence the kinetic energy of the second particle after collision is equal to 1-4/9=5/9 of the initial kinetic energy
of the first particle, so (4/9) * m1 * u2 / 2 = m1 * v12 / 2, (5/9) * m1 * u2 / 2 = m2 * v22 / 2,whence

v1 = 2/3 u, v2 = sqrt(5)/3 u,Substituing these values to the formula (A) we get:

m1*u = m1*u*2/3 + m2*u*sqrt(5)/3

Contracting by u we get

m1 = m1*2/3 + m2*sqrt(5)/3

m1/3 = m2*sqrt(5)/3

m1 / m2 = sqrt(5) = 2.236


Answer.
Thus the mass of the first particle in 2.2 times greater than the mass of the first particle

stevesmith3: mark my answer as brainliest
shreyasharma39: your answer is wrong
stevesmith3: Not
yubifabes: As far as I know, the answer just be 5mp.
Answered by anjaliyerpude1
79

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