A public bus in a city is as follows for the first two kilometers the fare is ₹12 for the subsequent distance it is ₹10 per km .Taking the distance covered as xkm and total fare as ₹y. Write a linear equation for this information and draw its graph.
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Given : for the first two kilometers the total fare is Rs. 12 and the subsequent distance is Rs. 10 per km
To find : a linear equation taking x as distance covered and y as fare.
Solution:
Distance Covered = x
Fare = y
for the first two kilometers the total fare is Rs. 12
the subsequent distance is Rs.10
y = 12 + 10(x - 2) x ≥ 2
= y = 12 + 10x - 20
= y = 10x - 8 where x ≥ 2
y = 10x - 8 where x ≥ 2
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