a public park in the form of square has an area of 100+-0.2 m^2. the side of park is
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area of square Park = (100 ± 0.2) m²
we know, area of square , A = L² , Where L is side length.
Given, A = 100
∴ L² = 100 = 10²
⇒ L = 10 m
For getting error , we have to apply formul,
∆A/A = 2∆L/L
Given, A = 100 , ∆A = 0.2 , L = 10
∆L = ?
∴ 0.2/100 = 2 × ∆L/10
⇒0.2/100 × 10 = 2 × ∆L
⇒ 0.02/2 = ∆L
⇒ ∆L = 0.01
Hence, side of park = (10 ± 0.01) m
we know, area of square , A = L² , Where L is side length.
Given, A = 100
∴ L² = 100 = 10²
⇒ L = 10 m
For getting error , we have to apply formul,
∆A/A = 2∆L/L
Given, A = 100 , ∆A = 0.2 , L = 10
∆L = ?
∴ 0.2/100 = 2 × ∆L/10
⇒0.2/100 × 10 = 2 × ∆L
⇒ 0.02/2 = ∆L
⇒ ∆L = 0.01
Hence, side of park = (10 ± 0.01) m
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9Solution:-
given by :-
a public park in the form of square has an area of 100+-0.2 m^2.
answer :- s+ delta(s ) = 10+0.01
☆i hope its help☆
given by :-
a public park in the form of square has an area of 100+-0.2 m^2.
answer :- s+ delta(s ) = 10+0.01
☆i hope its help☆
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