How much oxygen will be required to burn 8 gram of methane completely?
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Answers
Answered by
12
CH4 + 2O2 = CO2 + 2H2O
16 g methane = 64 g Oxygen
8 g methane = 32 g Oxygen
16 g methane = 64 g Oxygen
8 g methane = 32 g Oxygen
Answered by
7
Answer:
32g
Explanation:
CH4+2O2--- Co2+2H2O.
Now mass of methane is 16g and mass of oxygen is 64(4×16).
To burn 16g methane, 64g of oxygen is required and this way according to stoichiometry to burn 8g of methane we need = 64/18*8=32g....
Therefore, 32g of oxygen is required to burn 8g of methane completely......
;)...
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