Question

How much oxygen will be required to burn 8 gram of methane completely?
please answer it
I have to complete my homework

Answer 1

CH4 + 2O2 = CO2 + 2H2O

16 g methane = 64 g Oxygen

8 g methane = 32 g Oxygen

Answer 2

Answer:

32g

Explanation:

CH4+2O2--- Co2+2H2O.

Now mass of methane is 16g and mass of oxygen is 64(4×16).

To burn 16g methane, 64g of oxygen is required and this way according to stoichiometry to burn 8g of methane we need = 64/18*8=32g....

Therefore, 32g of oxygen is required to burn 8g of methane completely......

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