a pulse was created in a slinky of length 5 m by group of students .they observed that it returned,after ,reflection, at the point of creation 5 times in 10 seconds and calculated the speed as ?
Answers
Answered by
49
Given ;
length of the slinky = Wavelength = 5 m
Frequency = no. of oscillations/Time
= 5/10
= 0.5 Hz
----------------------------------------------------
Speed = f × ʎ
= 0.5 × 5
= 2.5 m/s
_____________________________
length of the slinky = Wavelength = 5 m
Frequency = no. of oscillations/Time
= 5/10
= 0.5 Hz
----------------------------------------------------
Speed = f × ʎ
= 0.5 × 5
= 2.5 m/s
_____________________________
Answered by
24
Given,
Distance = 5 m
Time = 10 / 5 sec
= 2 sec
&
We know that,
Speed = Distance / Time
= 5 / 2 m/s
= 2.5 m/s Ans.
Distance = 5 m
Time = 10 / 5 sec
= 2 sec
&
We know that,
Speed = Distance / Time
= 5 / 2 m/s
= 2.5 m/s Ans.
Anonymous:
The length of slinky = 5 m actually ....
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