Question

A pump can lift 9000 kg coal per hour from a mine of depth 120 m. Assuming its efficiency to be 75% its

power will be (in watts) -

[a] 3920 W [b] 2020 W [c] 3400 W [d] None of these


explain​

Answer 1

Answer:

Output power=9000*120*10=10800000/3600=3000

\frac{75x}{100} = 3000 \\ so \: x \: = 4000

so the power of pump is 4000watt

HOPE IT WILL HELP YOU.

Answer 2

Answer:

hope it helps

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