Question

a pump is required to lift 1000 kg of water in 1 minute from a well of depth 10 meter and eject it with a speed of 10 m/s the horse power of the pump is if g= 10m/s^2

Answer 1

Given:
Mass of water that has lifted=m=1000kg
time=t=1min=60sec
Height=h=10m
g=10m/s²
Ejected velocity=v=10m/s
Formula: Power=P= Workdone/Time
P= Potential energy +Kinetic energy/Time
=(mgh+1/2mv²)/time
=[(1000*10*10)+(1000*10*10)/2]/60
=(100000+50000)/60
=150000/60
=2500watts
∵ 1Horse power=746watts]
Power=2500/746=3.35hp
∴Horse power of engine is 3.35hp

Answer 2

Answer:

3.35 H.p

Explanation:

P.E=mgh

=1000×10×10

=100000J

K.E=1/2mv^2

=1/2×1000×10×10

=50000J

P=P.E+K.E/T

=100000+50000/60 (1min=60s)

=2500W

since,

1HP=746W

therefore,

2500W=3.35HP

THEREFORE REQUIRED ANSWER IS 3.35 HP

PLEASE MARK ME AS BRANLIEST ANSWER