A pump is required to lift 60 kg of water per minute from a well 25m deep and to eject it with a speed of 50ms -1 calculate the power required to perform the above task.
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can anybody tell me important q of sci. 10
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HEYA MATE HERE U GO.
Mass of water lifted (m) = 600kg
depth of well (h) = 25 m
work done to lift water (w1) = mgj = 600× 9.8 × 25 = 147000J
speed of water (v) = 50ms^-1
Mass of water (m) = 600kg
work done to given K.E to water , w2 = 1/2 mv^2 = 1/2 × 600 × 2500 = 750000 J
Total work done W = W1 + W 2 = 147000+ 750000= 897000J
Time taken (t) = 1 minute = 60s.
Therefore Power required = workdone /time = 89700/60 = 14950 w = 14.95 kW.
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