A pump is used to pump a liquid of density p
continuously through a pipe of cross section area
A. If liquid is flowing with speed V, then average
power of pump is
Answers
Answered by
19
Answer:
power=pAV³/2
Explanation:
power = work done /time taken
let us assume a small element X of the water released from the pump as shown in the figure above.
mass of the element = pAX
velocity of the mass = V
•°•, work done = ∆KE
=½×m×V²
=½×pAXV² .................(1)
•°•, power generated= work done /time taken
= ½×pAV² × (Vdt) /dt. {X=Vdt}
= ½×pAV³
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Answered by
7
Answer:
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