Physics, asked by nidhi6429, 1 year ago

A pump is used to pump a liquid of density p
continuously through a pipe of cross section area
A. If liquid is flowing with speed V, then average
power of pump is

Answers

Answered by muditgunwal
19

Answer:

power=pAV³/2

Explanation:

power = work done /time taken

let us assume a small element X of the water released from the pump as shown in the figure above.

mass of the element = pAX

velocity of the mass = V

•°•, work done = ∆KE

=½×m×V²

=½×pAXV² .................(1)

•°•, power generated= work done /time taken

= ½×pAV² × (Vdt) /dt. {X=Vdt}

= ½×pAV³

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Answered by Anonymous
7

Answer:

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