A pump on the ground floor of a building can pump up water to fill a tank of volume 40 m3 in 20 minutes.if the tank is 30 m above the ground and the efficiency of the pump is 40%.how much electrical power is consumed by the pump
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Answer:
Volume of the tank, V = 30 m3
Time of operation, t = 15 min = 15 × 60 = 900 s
Height of the tank, h = 40 m
Efficiency of the pump, η = 30 %
Density of water, ρ = 103 kg/m3
Mass of water, m = ρV = 30 × 103 kg
Output power can be obtained as:
P0 = Work done / Time = mgh / t
= 30 × 103 × 9.8 × 40 / 900 = 13.067 × 103 W
For input power Pi,, efficiency η, is given by the relation:
η = P0 / Pi = 30%
Pi = 13.067 × 100 × 103 / 30
= 0.436 × 105 W = 43.6 kW
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