Question

A pump on the ground floor of a building can pump up water to fill a tank of volume 40cm³ in 20minutes .If the tank is 30 m above the ground and the efficiency of 40% . How much electric power consumed by the pump.

Answer 1

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➧ The volume of the tank is
➾ 30 

➧ Mass of the water is
➾ 30 × 1000 kg
➾ 30000kg 

➧ Time = 15 min
➾ 15 × 60
➾ 900s 

➧ Height
➾ 40 m 

➧ Total work done by the pump
➾ F × h= mgh
➾ 30000 × 9.8 × 40
➾ 11760000 J 

➧ Power = W/t
➾ 11760000 / 900
➾ 13066.67 watt 

➧ Efficiency = 30%
➾ 3 / 10 

➧ Required power
➾ 13033.67 × 10 / 3
➾ 43.56 kW ...✔

_________
Thanks...✊

Answer 2

Answer:

Given, the volume of the tank = 30m^3

Mass of the water, m = 30*1000 kg = 30000kg

Time, t = 15 min = 15*60 = 900s

Height, h = 40 m

Total work done by the pump, W = F*h= mgh = 30000*9.8*40 = 11760000 J

Power, P = W/t = 11760000/900 = 13066.67 watt

But efficiency = 30% = 3/10

Required power, P = 13033.67*10/3 = 43.56 kW.