A purchases 5 chairs and 2 tables for Rs 1625. B purchased 2 chairs and 1 table for Rs 750 . The cost per chair and per table respectively are ....
Answers
Answered by
4
Let chairs be C and tables be T
So There are two persons A and B
For A.......... 5C + 2T = 1625
For B........... 2C + T = 1500
Now for subtracting multiply B by 2 and subtract 2 from 1 we get
cost per chair is 125 Rs and
cost per table is 500 Rs
So There are two persons A and B
For A.......... 5C + 2T = 1625
For B........... 2C + T = 1500
Now for subtracting multiply B by 2 and subtract 2 from 1 we get
cost per chair is 125 Rs and
cost per table is 500 Rs
Answered by
5
Let the cost of one table = Rs. x
the cost of one chair = Rs. y
cost of 5 chairs and 2 tables for Rs 1625
or 5y + 2x = 1625 --------------(1)
cost of 2 chairs and 1 table for Rs 750
or 2y + x = 750 -----------------(2)
(now you have two equations and two variables. You can solve them in any method you want.)
from equation (2), we can write that,
x = 750-2y
putting in equation (1),
5y + 2(750-2y) = 1625
⇒ 5y + 1500 - 4y = 1625
⇒ 5y - 4y = 1625 - 1500
⇒ y = 125 (cost of one chair)
x =750 - 2y = 750 - 2×125 = 750 - 250 = 500 (cost of one table)
Hence, cost per chair is Rs. 125 and cost per table is Rs. 500.
the cost of one chair = Rs. y
cost of 5 chairs and 2 tables for Rs 1625
or 5y + 2x = 1625 --------------(1)
cost of 2 chairs and 1 table for Rs 750
or 2y + x = 750 -----------------(2)
(now you have two equations and two variables. You can solve them in any method you want.)
from equation (2), we can write that,
x = 750-2y
putting in equation (1),
5y + 2(750-2y) = 1625
⇒ 5y + 1500 - 4y = 1625
⇒ 5y - 4y = 1625 - 1500
⇒ y = 125 (cost of one chair)
x =750 - 2y = 750 - 2×125 = 750 - 250 = 500 (cost of one table)
Hence, cost per chair is Rs. 125 and cost per table is Rs. 500.
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