Biology, asked by balubhat18, 11 months ago

A pure dominant pea plant producing
round yellow seeds is crossed with pure
recessive pea plant producing wrinkled
green seeds. The number of plants
bearing round green seeds in the F,
generation of Mendel's experiment is​

Answers

Answered by Anonymous
9

Answer:

all round green seeds is the answer.

Explanation:

see the attached pic for more information

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Answered by Anonymous
24

Mendel was known as the father of genetics. He worked with and crossed the two pea plants with one and two pairs of contrasting characters.

Cross between two pea plants having one contrasting character is known as Monohybird cross.

Whereas cross between two pea plants having two pairs of contrasting characters is known as Dihybrid cross.

In dihybrid cross; he made a cross between a plant having round yellow seeds and another pea plant having wrinkled seeds. Round yellow seeds were denoted by RRYY and wrinkled seeds were denoted by rryy. Both pea plants were homozygous in nature (RRYY and rryy).

In the first generation all progeny shows round yellow seeds (RrYy). As shown in attachment. Because round and yellow seeds both were dominant characters (which can express themselves in next generation) whereas green and wrinkled seeds are recessive character (which can't express themselves in next generation).

Therefore, number of plants bearing round seeds in F1 generation of Mendel's experiment are all round yellow seeds.

Why Mendel choose pea plant only?

→ Short life span.

→ Production of large number of seeds.

→ Availability of seven different contracting characters. (for study)

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ShivamKashyap08: Kya baat hai Kya baat hai.... Gajab ka answer hai....
Anonymous: Shukriya shukriya
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