Question

a pure inductor of 25 mh is connected to a 220 v and 50 hz frequncy fi d the inductive reactance and rms current of the circuit
​

Answer 1

The inductive reactance of the circuit is equal to 2.5π ohm.

The rms current flowing in the circuit is equal to 19.8 A.

L = 25 mH

f = frequency of AC = 50 Hz

X(L) = inductive reactance of the circuit = L× 2πf

= 25 × (10)^-3 × 50× 2π

= 2.5π ohm

RMS voltage of the circuit = peak voltage of the circuit / √2

= 220/√2

The RMS current of the circuit = RMS voltage / inductive reactance of the circuit

=> 220/(2.5π × √2)

=> 19.8 A

Answer 2

Answer:

Explanation:Best solution for this question.