Physics, asked by shaijalgaokar, 1 year ago

A pure resistance is connected to an a.c source of 220 V, 50 Hz. What will be the phase difference between the current and e.m.f in the circuit?

Answers

Answered by shubhamjoshi033
0

The phase difference between current and EMF in a circuit consisting of pure resistance is 0.

Explanation :

Let EMF = Vsin(wt + Ф)

since resistance does not have any reactive component, impedance of a resistive circuit is equal to R

=> Z = R

=> current = EMF/impedance

=> I = Vsin(wt + Ф)/R

=> I = (V/R)sin(wt + Ф)

Hence we can see the phase difference between both EMF and current is zero.

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