Question

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$<b>Point P divides the line segment joining the points A(2,1) and B(5,-8) such that AP:AB = 1:3. \ \textless \ br /\ \textgreater \ If P lies on the line 2x-y+k=0, then find the value of k.$

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Answer 1

here us ur answer...

AP/AB=
AP=3AB

3AP=AP+BP
2AP=BP
AP:BP=1:2

USING INTERNAL SECTION FORMULA USE THIS RATIO AND FIND THE POINT P

Answer 2

Answer:

here is ur answer.............