a purse contains 25 paisa 50 paisa coins.the number of 25 paisa coins is three times the number of 50 paisa coins.if the total money in the purse is 50rupes,find the number of coins of each type
Answers
Answered by
17
Let the number of 50 p coins be x.
Therefore, number of 25 p coins =3x.
Therefore value of 50 p coins = x/2 rupee
25 p coins = 3x/4 rupee
BTP x/2 + 3x/4 = 50
=> (2x + 3x)/ 4 = 50
=> 5x = 50*4
=> x = 200/5
=> x = 40
Therefore, number of 50 p coins = x = 40
25 p coins = 3x = 3*40 = 120
Therefore, number of 25 p coins =3x.
Therefore value of 50 p coins = x/2 rupee
25 p coins = 3x/4 rupee
BTP x/2 + 3x/4 = 50
=> (2x + 3x)/ 4 = 50
=> 5x = 50*4
=> x = 200/5
=> x = 40
Therefore, number of 50 p coins = x = 40
25 p coins = 3x = 3*40 = 120
Answered by
4
Answer:
The purse contains 40 coins of 50paise and 120 coins of 25paise.
Similar questions