CaCO3 = CaO + CO2
From the above equation calculate the amount of carbon dioxide in grams liberated by heating 25g of calcium carbonate
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from equation
1mole. caco3 react to make 1mole co2
so we will take mole ratio
ncaco3/nco2. = 1/1
(given weight/molecular weight = n )
25/100 / x/44. = 1/1
11 = x
therefor 11gm co2 produced..
may you get this....... thanks
1mole. caco3 react to make 1mole co2
so we will take mole ratio
ncaco3/nco2. = 1/1
(given weight/molecular weight = n )
25/100 / x/44. = 1/1
11 = x
therefor 11gm co2 produced..
may you get this....... thanks
diya52:
dint understnd dat 25/100
25 gm caco3 was given in question.. and. 100 is molecular wieght of caco3
oh ok
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