Question

A purse contains 342 coins consisting of one rupees, 50 paise and 25 paise coins. if their values are in the ratio of 11 : 9 : 5 then find the number of 50 paise coins?

Answer 1

I think your question may be:

A purse contains 392 coins consisting of one rupees, 50 paise and 25 paise coins. if their values are in the ratio of 11 : 9 : 5 then find the number of 50 paise coins?

$\textsf{Let x,y and z be the number of coins in each caegory Re.1, Re.0.5 and Re.0.25 respectively}$

$\textsf{As per given data,}$

$\mathsf{x+y+z=392}$......(1)

$\mathsf{x:0.5y:0.25z=11:9:5}$

$\implies\,\mathsf{x=11k,\;0.5y=9k,\;0.25z=5k}$

$\implies\,\mathsf{x=11k,\;y=18k,\;z=20k}$

$\textsf{(1)\,becomes}$

$\mathsf{11k+18k+20k=392}$

$\mathsf{49k=392}$

$\implies\mathsf{k=8}$

$\therefore\textsf{The number of 50 paise coins is 18{\times}8=144 }$

Answer 2

Answer:

Step-by-step explanation:

i think total number of coins mistakenly written as 342 ,by putting 441 coins you'll get right answer which is 162.

the coins of one rupee, 50 paisa and 25 paisa will come out 99, 162 and 180 respectively.