A purse contains 4 copper and 3 silver coins.the second purse has 6 copper and 2 silver coins. A coin is taken out. The probability that it is a copper coin will be
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Total no of copper coins = 4 + 6 =10,
No of silver coins = 3+2 =5
, total no of coins = 10+5=15
P( getting a copper coin ) = no of copper coins / total coins = 10/15=2/3 ans
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total no. of coins in 1st purse = 4+ 3 = 7.
total no. o coins in 2nd purse = 6+ 2 = 8
no. of silver coins in both = 3+ 2 = 5
no. of copper coins in both = 4+ 6 + 10
probability of a copper coin will be the total no. of copper coin/ total no. of coins in all.
= 10 / 15
= 2/3
total no. o coins in 2nd purse = 6+ 2 = 8
no. of silver coins in both = 3+ 2 = 5
no. of copper coins in both = 4+ 6 + 10
probability of a copper coin will be the total no. of copper coin/ total no. of coins in all.
= 10 / 15
= 2/3
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